D and F Block Elements - NCERT Based MCQ Questions for NEET Exam

This article contains NCERT based 45 MCQ questions test on Chemistry chapter "D and F Block Elements". These questions are highly valuable for the NEET exam. You can attempt these questions in the form of an interactive quiz and calculate your score. Read the below quiz rules carefully before you start

General Instructions

• Quiz contains 45 questions of 4 marks each.
• Correct answer (✔) will award you +4 marks and Incorrect answer (✘) will give you -1 mark.
• Total test is of 180 marks.
• Tap on box in order to select any option that you think is correct.
• Press the Submit button given in the end of quiz to calculate your score.
• There is a PDF file attached in the end of quiz. You can see detailed solutions to all questions and do self analysis from that file as well.

Question 1. Arrange Ce³⁺, La³⁺, Pm³⁺, and Yb³⁺ in increasing order of their ionic radius -

(1) Yb³⁺ < Pm³⁺ < Ce³⁺ < La³⁺

(2) Ce³⁺ > Yb³⁺ < Pm³⁺ < La³⁺

(3) Yb³⁺ > Pm³⁺ < La³⁺ < Ce³⁺

(4) Pm³⁺ < La³⁺ < Ce³⁺ < Yb³⁺

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Question 2. What would happen when a solution of potassium chromate is treated with an excess of dilute nitric acid -

(1) Cr³⁺ and Cr₂O₇^2– are formed

(2) Cr₂O₇^2– and H₂O are formed

(3) Cr₂O₇^2– is reduced to +3 state of Cr

(4) Cr₂O₇^2– is oxidized to +7 state of Cr

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Question 3. The atomic number of vanadium (V), chromium (Cr), manganese (Mn) and iron (Fe) are 23, 24, 25 and 26 respectively. Which one of these may be expected to have the highest second ionization enthalpy -

(1) V

(2) Cr

(3) Mn

(4) Fe

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Question 4. The radius of La³⁺ is 1.06 Å, which of the following given values will be closest to the radius of Lu³⁺. (At no. of Lu = 71, La = 57)

(1) 1.6 Å

(2) 1.4 Å

(3) 1.06 Å

(4) 0.85 Å

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Question 5. Cerium (Z = 58) is an important member of the lanthanoids. Which of the following statement about cerium is incorrect

(1) Cerium (IV) acts as an oxidising agent.

(2) The +3 oxidation state of cerium is more stable than the +4 oxidation state.

(3) The +4 oxidation state of cerium is not known in solutions.

(4) The common oxidation states of cerium are +3 and +4.

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Question 6. Excess of KI reacts with CuSO₄ solution and then Na₂S₂O₃ solution is added to it. Which of the statements is incorrect for this reaction –

(1) Evolved I₂ is reduced

(2) CuI₂ is formed.

(3) Na₂S₂O₃ is oxidized

(4) Cu₂I₂ is formed.

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Question 7. Lanthanoid contraction is caused due to -

(1) the same effective nuclear charge from Ce to Lu.

(2) the imperfect shielding on outer electrons by 4f electrons from the nuclear charge.

(3) the appreciable shielding on outer electrons by 4f electrons from the nuclear charge.

(4) the appreciable shielding on outer electrons by 5d electrons from the nuclear charge.

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Question 8. Identify the incorrect statement among the following

(1) d-block elements show irregular and erratic chemical properties among themselves.

(2) La and Lu have partially filled d-orbitals and no other partially filled orbitals.

(3) The chemistry of various lanthanoids is very similar.

(4) 4f and 5f-orbitals are equally shielded.

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Question 9. In context with the transition elements, which of the following statements is incorrect?

(1) In the highest oxidation states, the transition metal show basic character and form cationic complexes.

(2) In the highest oxidation states of the first five transition elements (Sc to Mn), all the 4s electrons are used for bonding.

(3) Once the d5 configuration is exceeded, the tendency to involve all the 3d electrons in bonding decreases.

(4) In addition to the normal oxidation states, the zero oxidation state is also shown by these elements in complexes.

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Question 10. The number of 3d-electrons remained in Fe²⁺ (At. no. of Fe = 26) is –

(1) 4

(2) 5

(3) 6

(4) 3

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Question 11. The correct order of E°_M²⁺/M values with negative sign for the four successive elements Cr, Mn, Fe and Co is

(1) Mn > Cr > Fe > Co

(2) Cr > Fe > Mn > Co

(3) Fe > Mn > Cr > Co

(4) Cr > Mn > Fe > Co2

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Question 12. In context of the lanthanoids, which of the following statement is not correct?

(1) There is a gradual decrease in the radii of the members with increasing atomic number in the series.

(2) All the member exhibit +3 oxidation

state.

(3) Because of similar properties the separation of lanthanoids is not easy.

(4) Availability of 4f electrons results in the formation of compounds in +4 state for all the members of the series.

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Question 13. Which of the following arrangements does not represent the correct order of the property

stated against it?

(1) Number of oxidation states : Sc < Ti < Cr < Mn

(2) Paramagnetic behaviour : V²⁺ < Cr²⁺ < Mn²⁺ < Fe²⁺

(3) Ionic size : Ni²⁺ < Co²⁺ < Fe²⁺ < Mn²⁺

(4) Stability in aqueous solution : Co³⁺ < Fe³⁺ < Cr³⁺ < Sc³⁺

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Question 14. The salts of Cu in +1 oxidation state are unstable because

(1) Cu⁺ has 3d¹⁰ configuration

(2)Cu⁺ disproportionates easily to Cu(0) & Cu²⁺

(3)Cu⁺ disproportionates easily to Cu²⁺ & Cu³⁺

(4) Cu⁺ is easily reduced to Cu²⁺

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Question 15. If KMnO₄ is reduced by oxalic acid in an acidic medium, then oxidation number of Mn changes from

(1) 4 to 2

(2) 6 to 4

(3) 7 to 2

(4) 7 to 4

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Question 16. The trend of basicity of lanthanoid hydroxides

(1) Increases across the lanthanoid series

(2) Decreases across the lanthanoid series

(3) First increases and then decreases

(4) First decreases and then increases.

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Question 17. Preparation of looking mirrors involves the use of

(1) Red lead

(2) Ammoniacal silver nitrate

(3) Ammoniacal AgNO₃ + red lead

(4) Ammoniacal AgNO₃ + red lead + HCHO

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Question 18. Why is HCl not used to make the medium acidic in oxidation reactions of KMnO₄ in

acidic medium?

(1) Both HCl and KMnO₄ act as oxidizing agents.

(2) KMnO₄ oxidizes HCl into Cl₂ which is also an oxidizing agent.

(3) KMnO₄ is a weaker oxidizing agent than HCl.

(4) KMnO₄ acts as a reducing agent in the presence of HCl.

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Question 19. The magnetic nature of elements depends on the presence of unpaired electrons. Identify the configuration of transition elements, which shows highest magnetic moment

(1) 3d⁷

(2) 3d⁵

(3) 3d⁸

(4) 3d²

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Question 20. The correct order of number of unpaired electrons is

(1) Cu²⁺ > Ni²⁺ > Cr³⁺ > Fe³⁺

(2) Ni²⁺ > Cu²⁺ > Fe³⁺ > Cr³⁺

(3) Fe³⁺ > Cr³⁺ > Ni²⁺ > Cu²⁺

(4) Cr³⁺ > Fe³⁺ > Ni²⁺ > Cu²⁺

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Question 21. Highest oxidation state of manganese in fluoride is +4 (MnF4) but highest oxidation

tate in oxides is +7 (Mn₂O₇) because

(1) Fluorine is more electronegative than oxygen.

(2) Fluorine does not possess d-orbitals.

(3) Fluorine stabilises lower oxidation state.

(4) In covalent compounds, fluorine can form single bond only while oxygen forms double bond

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Question 22. Native silver metal forms a water-soluble complex with a dilute aqueous solution of NaCN in the presence of

(1) Nitrogen

(2) Oxygen

(3) Carbon

(4) Argon

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Question 23. Due to lanthanoid contraction which of the following properties is not expected to be

similar in the same vertical columns of second and third row transition elements?

(1) Atomic radii

(2) Ionization energies

(3) Magnetic moments

(4) Lattice energies

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Question 24. Acidified potassium permanganate solution is decolorized by

(1) Bleaching powder

(2) White vitriol

(3) Mohr’s salt

(4) Microcosmic salt

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Question 25. Following order is observed in oxidizing

power of certain ions: VO₂⁺ < Cr₂O₇^2– < MnO₄^–

The reason for this increasing order of oxidizing power is

(1) Increasing stability of the lower species to which they are reduced.

(2) Increasing stability of the higher species to which they are oxidized.

(3) Increasing stability of the higher species to which they are reduced.

(4) Increasing stability of the lower species to which they are oxidized.

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Question 26. Choose the correct statement –

(a) The lowest oxide of transition metal is basic, the highest is acidic.

(b) A transition metal exhibits higher oxidation states in oxides and fluorides.

(1) only (a) (2) only (b)

(3) Both (a) and (b) (4) None of these

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Question 27. Electronic configuration of a transition element X in +3 oxidation state is [Ar]3d⁵.

What is its atomic number?

(1) 25

(2) 26

(3) 27

(4) 24

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Question 28. Mercury is the only metal which is liquid at 0°C. This is due to its

(1) Very high ionization energy and weak metallic bond.

(2) Low ionization potential

(3) High atomic weight

(4) High vapor pressure

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Question 29. Which of the following statements is not correct?

(1) Copper liberates hydrogen from acids.

(2) In higher oxidation states, manganese forms stable compounds with oxygen and fluorine.

(3) Mn³⁺ and Co³⁺ are oxidizing agents in aqueous solution.

(4) Ti²⁺ and Cr²⁺ are reducing agents in aqueous solution.

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Question 30. Which group contains colored ions out of the following?

1. Cu⁺

2. Ti⁴⁺

3. Co²⁺

4. Fe²⁺

(1) 1, 2, 3, 4

(2) 3, 4

(3) 2, 3

(4) 1, 2

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Question 31. Transition metals react with halogen at elevated temperature to form halides. The reactivity order of halogens are

(1) F₂ > Cl₂ > Br₂ > I₂

(2) Cl₂ > F₂ > Br₂ > I₂

(3) I₂ > Br₂ > Cl₂ > F₂

(4) Cl₂ < F₂ > I₂ > Br₂

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Question 32. CuSO₄ is paramagnetic while ZnSO₄ is diamagnetic because

(1) Cu²⁺ ion has 3d⁹ configuration while Zn²⁺ ion has 3d¹⁰ configuration.

(2) Cu²⁺ ion has 3d⁵ configuration while Zn²⁺ ion has 3d⁶ configuration.

(3) Cu²⁺ has half-filled orbitals while Zn²⁺ has fully filled orbitals.

(4) CuSO₄ is blue in color while ZnSO₄ is white.

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Question 33. Generally transition elements form colored salts due to the presence of unpaired electrons. Which of the following compounds will be colored in solid state?

(1) Ag₂SO₄

(2) CuF₂

(3) ZnF₂

(4) Cu₂Cl₂

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Question 34. The basic character of the transition metal monoxides follows the order. (Atomic numbers Ti = 22, V = 23, Cr = 24, Fe = 26)

(1) VO > CrO > TiO > FeO

(2) CrO > VO > FeO > TiO

(3) TiO > FeO > VO > CrO

(4) TiO > VO > CrO > FeO

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Question 35. The magnetic moment is associated with its spin angular momentum and orbital angular

momentum. Spin only magnetic moment value of Cr³⁺ ion is

(1) 2.87 B.M.

(2) 3.87 B.M.

(3) 3.47 B.M.

(4) 3.57 B.M.

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Question 36. Match the column I with column II and mark the appropriate choice

Column I Column II

(a) Ni in the presence(i) Ziegler Natta of hydrogen catalyst

(b) Cu₂Cl₂ (ii) Contact process

(c) V₂O₅ (iii) Vegetable oil to ghee

(d) Finely divided iron (iv) Sandmeyer reaction

(e) TiCl₄ + Al(CH₃)₃ (v) Haber’s Process

(1) a-iv, b-ii, c-iii, d-i, e-v

(2) a-ii, b-v, c-i, d-iii, e-iv

(3) a-v, b-iii, c-iv, d-ii, e-i

(4) a-iii, b-iv, c-ii, d-v, e-i

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Question 37. Articles made of copper and bronze slowly tarnish in air and turn green. The green color is due to the formation of

(1) Copper oxide

(2) Copper sulphide

(3) Copper oxalate

(4) Basic copper carbonate

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Question 38. The second and third row elements of transition metals resemble each other much more than they resemble the first row because of

(1) Lanthanoid contraction which results in almost same radii of second and third row metals.

(2) Diagonal relationship between second and third row elements.

(3) Similar ionization enthalpy of second and third row elements.

(4) Similar oxidation states of second and third row metals.

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Question 39. Most of the transition metals exhibit

(i) Paramagnetic behavior

(ii) Diamagnetic behavior

(iii) Variable oxidation states

(iv) Formation of colored ions

(1) ii, iii and iv

(2) i, iii and iv

(3) i, ii and iii

(4) i, ii and iv

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Question 40. A violet compound of manganese (P) decomposes on heating to liberate oxygen and

compounds (Q) and (R) of manganese are formed. Compound (R) reacts with KOH in the presence of potassium nitrate to give compound (Q). On heating compound (R) with conc. H₂SO₄ and NaCl, chlorine gas is liberated and a compound (S) of manganese along with other products is formed.

Compounds P to S are :

(1) P-KMnO₄, Q- K₂MnO₄, R-MnCl₂,S-MnO₂

(2) P-K₂MnO₄, Q-MnO₂, R-KMnO₄,S-MnCl₂

(3) P-KMnO₄, Q-K₂MnO₄, R-MnO₂,S-MnCl₂

(4) P-K₂MnO₄, Q-KMnO₄, R-MnO₂,S-MnCl₂

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Question 41. Which of the following element does not belong to first transition series?

(1) Fe

(2) V

(3) Ag

(4) Cu

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Question 42. The metals of Group-12 are softer than other transition metals because

(1) Group-12 metals have a cage-like structure.

(2) Group-12 metals have high ionization energies.

(3) s-as well as d-electrons take part in metallic bonding.

(4) d-electrons do not take part in metallic bonding.

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Question 43. The aqueous solution containing which one of the following ions will be colorless?

(Atomic no. Sc = 21, Fe = 26, Ti = 22, Mn = 25)

(1) Sc³⁺

(2) Fe²⁺

(3) Ti³⁺

(4) Mn²⁺

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Question 44. The main reason for larger number of oxidation states exhibited by the actinoids than the corresponding lanthanoids is –

(1) More energy difference between 5f and 6d orbitals than between 4f and 5d orbitals.

(2) Lesser energy difference between 5f and 6d orbitals than between 4f and 5d orbitals.

(3) Larger atomic size of actinoids than the lanthanoids.

(4) Greater reactive nature of the actinoids than the lanthanoids.

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Question 45. In which of the following pairs are both the ions colored in aqueous solutions –

(1) Sc³⁺, Ti³⁺

(2) Sc³⁺, Co²⁺

(3) Ni²⁺, Cu⁺

(4) Ni²⁺, Ti³⁺

(At. No. Sc = 21, Ti = 22, Ni = 28, Cu = 29, Co = 27)

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Detailed Solutions

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